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Posted by on Monday, October 6, 2008 at 8:45am.

Larry leaves home at 2:08 and runs at a constant speed to the lamppost. He reaches the lamppost at 2:15, immediately turns, and runs to the tree. Larry arrives at the tree at 2:29. What is Larry's average velocity during his trip from home to the lamppost, if the lamppost is 308.0 m west of home, and the tree is 688.0 m east of home?

  • physics - , Monday, October 6, 2008 at 10:57am

    velocity is change of position (a vector) per time.

    change of position: final position-initial
    = 688E+308W=380W

    avgvelocity=380W/total time.

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