• Post a New Question
• Current Questions
• Chat With Live Tutors

Homework Help: physics

Posted by Vishnu on Monday, October 6, 2008 at 8:45am.

Larry leaves home at 2:08 and runs at a constant speed to the lamppost. He reaches the lamppost at 2:15, immediately turns, and runs to the tree. Larry arrives at the tree at 2:29. What is Larry's average velocity during his trip from home to the lamppost, if the lamppost is 308.0 m west of home, and the tree is 688.0 m east of home?

• physics - bobpursley, Monday, October 6, 2008 at 10:57am

  velocity is change of position (a vector) per time.
  
  change of position: final position-initial
  = 688E+308W=380W
  
  avgvelocity=380W/total time.
  

Answer this Question

First Name:
School Subject:
Answer:

Related Questions

physics - Larry leaves home at 2:08 and runs at a constant speed to the lamppost...
physics - Larry leaves home at 1:01 and runs at a constant speed to the lamppost...
Physics - Larry leaves home at 3:02 and runs at a constant speed to the lamppost...
Physics - Larry leaves home at 3:02 and runs at a constant speed to the lamppost...
Physics - Larry leaves home at 2:08 and runs at a constant speed to the lamppost...
Physics - rry leaves home at 4:07 and runs at a constant speed to the lamppost. ...
physics - Larry leaves home at 2:08 and runs at a constant speed to the lamppost...
physics - Larry leaves home at 2:08 and runs at a constant speed to the lamppost...
Calculus - A man 2m tall walks away from a lamppost whose light is 5m above the ...
Geometry - Jonathan is 3 ft from a lamppost that is 12 ft high. The lamppost ...

For Further Reading