a golfer rides in a golf cart at an average speed of 3.10 meters/sec for 28.0 sec. she then gets out of the cart and starts walking at an average speed of 1.30 m/s. for how long in seconds must she walk if her average speed for the entire trip, riding and walking is 1.8m/s?
Use the equation
Average speed =
(total distance travelled)/time
1.8 m/s =
[(3.1 * 28.0) + 1.30 t]/(t + 28)
t is the time spent walking. Solve for it
0.81
To find the time the golfer must walk, we can use the formula:
Average speed = Total distance ÷ Total time
First, let's find the distance covered by the golfer while riding in the cart.
Distance covered while riding = Average speed while riding × Time spent riding
Distance covered while riding = 3.10 m/s × 28.0 s
= 86.8 meters
Now, let's assume the time the golfer must walk is represented by "t" seconds.
Therefore, the time spent walking = t seconds.
We know that the average speed for the entire trip, including riding and walking, is 1.8 m/s.
Using the formula for average speed, we can write:
1.8 m/s = (86.8 meters + Distance covered while walking) ÷ (28.0 s + t s)
Simplifying, we get:
1.8 m/s = (86.8 meters + 1.3 m/s × t s) ÷ (28.0 s + t s)
Now, we can solve for the time the golfer must walk, "t".
1.8(28.0s + t s) = 86.8 + 1.3t
50.4s + 1.8t = 86.8 + 1.3t
0.5t = 36.4
t ≈ 72.8 seconds
Therefore, the golfer must walk for approximately 72.8 seconds to maintain an average speed of 1.8 m/s for the entire trip.