Posted by jan on .
the price p and the quantity x sold of a certain product obey the demand equation
p=(1/3)x + 100
o is < or equal to x < or equal to 300
A) express revenue R as a function of x
b) what quantity x maximizes revenue.

math 
bobpursley,
Revenue=p*x
you finish..
Take the deriviative of R with respect to x, set to zero, solve for x. 
math 
jan,
so would the revenue be
(1/3)x + 100 * 300
I don't understand how would you multiply by x is its inequalities?
Also, what is the deriviative?