Posted by **jan** on Sunday, October 5, 2008 at 3:52pm.

the price p and the quantity x sold of a certain product obey the demand equation

p=(-1/3)x + 100

o is < or equal to x < or equal to 300

A) express revenue R as a function of x

b) what quantity x maximizes revenue.

- math -
**bobpursley**, Sunday, October 5, 2008 at 3:55pm
Revenue=p*x

you finish..

Take the deriviative of R with respect to x, set to zero, solve for x.

- math -
**jan**, Sunday, October 5, 2008 at 4:08pm
so would the revenue be

(-1/3)x + 100 * 300

I dont understand- how would you multiply by x is its inequalities?

Also, what is the deriviative?

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