"Luke Skywalker mixes 250g of hot water (75 deg C) with 500g of cool water (15 deg C). What is the final temperature of the water?"
If someone could just give me a formula, I'd be fine. :)
heat lost by hot water + heat gained by cold water = 0
mass H2O x specific heat water x delta T + (mass H2O x specific heat water x delta T) = 0
For delta T in each case substitute Tf - Ti (for Tf = final T and Ti = initial T). You will have only one unknown, namely Tf. Solve for that.
To find the final temperature of the water after mixing, you can use the principle of heat transfer, which states that the heat lost by the hot water is equal to the heat gained by the cool water.
The formula to calculate the final temperature is:
(m1 * T1 + m2 * T2) / (m1 + m2) = Tf
where:
m1 = mass of the hot water
T1 = initial temperature of the hot water
m2 = mass of the cool water
T2 = initial temperature of the cool water
Tf = final temperature of the water
Let's use these values in the formula to calculate the final temperature.
Given:
m1 (mass of the hot water) = 250 g
T1 (initial temperature of the hot water) = 75°C
m2 (mass of the cool water) = 500 g
T2 (initial temperature of the cool water) = 15°C
Using the formula:
(250g * 75°C + 500g * 15°C) / (250g + 500g) = Tf
Calculating:
(18750 + 7500) / 750 = Tf
26250 / 750 = Tf
Tf ≈ 35°C
Therefore, the final temperature of the water after mixing is approximately 35°C.