posted by Harmony on .
Given the reaction:
Fe2O3 + Al -> Fe Al2O3
What masses of iron oxide and aluminum must be used to produce 15g iron?
What is the maximum mass of aluminum oxide that could be produced?
How much aluminum oxide would be produced if the yield is 93%?
Please show solutions. :]
One has to start by balancinge the equation. Do that.
Then convert the 15g of iron to moles. Do that. THen, you know the mole relations ships between the iron and the reactants, and how many moles of reactants you need.
We will be happy to critique your work.
(Broken Link Removed)
The balanced equation would be
Fe2O3 Al -> Fe + Al2O3
15g of iron = .03 moles (rounded-off)