Posted by Claudia on Friday, October 3, 2008 at 8:32pm.
It is still going 1.61 m/s horizontal if it was going that speed originally.
Vertical the speed is:
v = Vo + a t, the initial speed down, Vo, is zero
v = 0 - 9.8 t
what is t, the time to fall 1.3 m?
h = ho + Vo t + .5 a t^2
-1.3 = 0 + 0 - 4.9 t^2
t = .515 s
so
v = -9.8 * .515 = -5.05 m/s
speed = sqrt (-5.05^2 + 1.61^2)
= sqrt ( 25.5+2.59)
=5.3 m/s
tan angle to horizontal = 5.05/1.61 = 3.14
angle down from horizontal = 72.3 degrees down from horizontal
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