arramge terms in each polynomial in ascending powers of y.
y^3+xy^2+y+2-2x^2t+3xy^3+x^3
please help.
you have everything except the y cubed right.
change that to
y^3(1+3x) + ... and you have it.
oops, you asked for ascending...
(2-2x^2t+x^3)y^0+ y + xy^2 + y^3(1+3x)
To arrange the terms in each polynomial in ascending powers of y, we need to rewrite the polynomials so that the terms with the lowest powers of y come first, followed by terms with higher powers of y.
Let's rearrange the given polynomial, y^3 + xy^2 + y + 2 - 2x^2t + 3xy^3 + x^3, in ascending powers of y.
First, let's collect all the terms with y^3:
y^3 + 3xy^3
Next, let's collect all the terms with y^2:
xy^2
Next, let's collect all the terms with y:
y
Now, let's collect all the constant terms:
2 - 2x^2t + x^3
Putting it all together, the rearranged polynomial in ascending powers of y is:
3xy^3 + y^3 + xy^2 + y + x^3 - 2x^2t + 2
Therefore, the polynomial rearranged in ascending powers of y is:
3xy^3 + y^3 + xy^2 + y + x^3 - 2x^2t + 2.