Posted by House on .
Use the law of cosines to solve ABC with A=126.3, b=45, and c=62.5
I did all the work to find a but my problem is finding B
a=96.2
Sin(B)=45sin126.3/96.2
B=Sin^1(45sin126.3/96.2)
It's not going through in my calculator

Math 
bobpursley,
I would use the law of sines to find angle B.
SineB/b=SinA/a 
Math 
House,
Sin(B)/45=126.3/96.2
im stuck there 
Math 
House,
B=1.03 and C=52.67