Greetings:

I was wondering how to calculate the weight/volume % of vinegar using the formula ---------------w/v Per Cent = g/100 mL or grams per deciliter:
WHAT WEIGHT DO I USE NaOH, Acetic ACID?
the data include:
volume of NaOH needed to neutralize Vingegar : 14.24 mL
Volume of Vinegar titrated: 5 mL
molarirty of the vinegar : 0.7776128491 mol/L

Calculated W/V % (g/100 mL) Acetic Acid? _____

Thank you for your help!

Assuming you have determined the molarity accurately (I assume you titrated the vinegar with the NaOH), you have M = # mols/L. How many mols are in the 5 mL sample? That will be 0.7776 x 0.005 L = ?? and that times the molar mass of acetic acid will give you grams acetic acid in the 5 mL. Multiply that by 100/5 to convert to g/100 and g/100 is percent. Check my thinking.

To calculate the weight/volume percentage of acetic acid in vinegar, you need to use the formula:

w/v Percent = (g / mL) × 100

Where:
- "g" is the weight of acetic acid in grams
- "mL" is the volume of vinegar in milliliters

In this case, you have the volume of NaOH needed to neutralize vinegar and the volume of vinegar titrated. The volume of vinegar titrated is already given as 5 mL.

To find the weight of acetic acid, you need to calculate the moles of NaOH used. The reaction between acetic acid (CH3COOH) and sodium hydroxide (NaOH) is as follows:

CH3COOH + NaOH -> CH3COONa + H2O

From the balanced equation, you can see that the mole ratio of acetic acid to NaOH is 1:1. This means that the moles of NaOH used will be equal to the moles of acetic acid present in the volume of vinegar titrated.

To find the moles of NaOH, you can use the molarity of vinegar and the volume of NaOH used:

moles of NaOH = molarity of vinegar × volume of NaOH (in L)

First, convert 14.24 mL to liters: 14.24 mL ÷ 1000 = 0.01424 L

Now, calculate the moles of NaOH:

moles of NaOH = 0.7776128491 mol/L × 0.01424 L = 0.0110741483 mol

Since the mole ratio of acetic acid to NaOH is 1:1, the moles of acetic acid present in the volume of vinegar titrated is also 0.0110741483 mol.

Now, to find the weight of acetic acid, you need to multiply the moles of acetic acid by its molar mass. The molar mass of acetic acid is 60.052 g/mol.

weight of acetic acid = moles of acetic acid × molar mass of acetic acid
weight of acetic acid = 0.0110741483 mol × 60.052 g/mol

Finally, substitute the weight of acetic acid and the volume of vinegar into the formula for weight/volume percentage:

w/v Percent = (weight of acetic acid / volume of vinegar) × 100
w/v Percent = (0.0110741483 mol × 60.052 g/mol / 5 mL) × 100

Now you can calculate the weight/volume percentage (w/v %) of acetic acid in vinegar by substituting in the values.