Posted by Matthew on Wednesday, October 1, 2008 at 9:15pm.
Assuming you have determined the molarity accurately (I assume you titrated the vinegar with the NaOH), you have M = # mols/L. How many mols are in the 5 mL sample? That will be 0.7776 x 0.005 L = ?? and that times the molar mass of acetic acid will give you grams acetic acid in the 5 mL. Multiply that by 100/5 to convert to g/100 and g/100 is percent. Check my thinking.
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