A stone is dropped in water from a bridge 44 cm above the water. Another stone is thrown straight down 1.0 s after the first one dropped. Both strike the water at the same time. What was the initial speed of the second stone?
12th grade Physics - bobpursley, Wednesday, October 1, 2008 at 8:38pm
first stone: .44=1/2 g t^2
second stone: .44=v(t-1)+1/2 g (t-1)^1
use equation 1) TO solve for t, then put it in equation 2) and solve for v.
12th grade Physics - ziaul, Saturday, October 4, 2008 at 12:37am
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12th grade Physics - Zainab Almosawi, Sunday, October 5, 2008 at 6:08pm