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April 18, 2014

April 18, 2014

Posted by **Anonymous** on Wednesday, October 1, 2008 at 6:07pm.

Express the series 11+18+27+...171 using sigma notation.

a1+a2+a3+...ak

11+18+27+...171

- Math -
**Kate**, Thursday, May 7, 2009 at 6:45pmS = 11 + 18 + 27 + 38 + 51 + 65 + 82 + .........+Tn

S = 11 + 18 + 27 + 38 + 51 + 65 + ................ + Tn

--------------------------------------...

0 = 11 + (7 + 9 + 11 + 13 + ....(n-1).terms.................) - Tn

0 = 11 + (n - 1)/2 [14 + 2(n - 2)] = 11 + (n - 1)(n + 5) - Tn

Tn = n^2 + 4n + 6. The given series in sigma notation is as follows.

SIGMA[k^2 + 4k + 6] the lower limit being k = 1 and the upper limit k = n

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