posted by natash .
For the reaction shown, find the limiting reactant for each of the following initial amounts of reactants.
4Al(s)+3O2 (g)-->2Al2O3 (s)
4 mol Al
2.6 mol O2
The equation tells you that 4 mol Al will require 3 mol O2. You have only 2.6 mol O2; therefore, O2 must be the limiting reagent.