A sample of oxalic acid, H2C2O4, weighing 1.294 g is placed in a 100.0 mL volumetric flask, which is then filled to the mark with water. What is the molarity of the solution?
Chem - DrBob222, Wednesday, October 1, 2008 at 12:13am
Remember the definition of molarity.
M = # mols/L.
Convert 1.294 g H2C2O4 to mols.
Then #mols/0.1 L = ??M
Chem - Brittany, Wednesday, October 1, 2008 at 12:30am
would the moles be .014?
Chem - DrBob222, Wednesday, October 1, 2008 at 10:56am
Close. The # mols = 1.294/90.035 = 0.014406 which rounds to 0.01441. You have 4 significant figures in 1.294; therefore, you may have that many in the answer.