physics
posted by mb on .
An artillery shell is fired with an initial velocity of 300 m/s at 55 degrees above the horizontal. to clear an avalanche, it explodes on a mountainside 42 sec after firing. what is the xcoordinate of the shell where it explodes, relative to its firing point?
An artillery shell is fired with an initial velocity of 300 m/s at 55 degrees above the horizontal. to clear an avalanche, it explodes on a mountainside 42 sec after firing. What is the ycoordinate of the shell where it explodes, relative to its firing point?

ok, so you have to find the cos of xaxis: v*cos=(300m/s)cos 55 degrees, and then the sin of your yaxis: v*sin= (300m/s)sin 55 degrees. The vx (xaxis)is always constant.
Then you have to use the formula: x=x(i)*t+ 1/2axt^2 to get the x coordinate, y=y(i)*t +1/2ayt^2. That'll give you the y coordination. Hope that helps you..Good luck!