Posted by tammy on Tuesday, September 30, 2008 at 6:01pm.
Mr. Jackson is preparing bags of treats to give trick or treaters on Halloween. He has 48 pieces of candy and 60 pieces of gum. He uses all the candy and gum, and he puts the same ratio of candy to gum in each bag. What is the largest number of bags he could have made?

math  bobpursley, Tuesday, September 30, 2008 at 6:06pm
What is the smallest common factor of 48 and 60? I will be happy to check your thinking.

math  tammy, Tuesday, September 30, 2008 at 6:11pm
48, but it says he uses all the candy and gum

math  bobpursley, Tuesday, September 30, 2008 at 6:25pm
The smallest common factor of each is 2, 3, 4, and up. Now the trick is to look at the ratio
48/60=reduces to 3/4 Since both the numberator and the denominator are common factors, then use these: 3 pieces of candy and 4 pieces of gum. Now you can answer the question.

math  helen, Saturday, December 10, 2011 at 8:36pm
13 because 48/60 reduces to 4/5.THE ANSWER IS EITHER 12 OR 13. NOT 7!!!

math  amanda, Tuesday, August 26, 2014 at 7:11pm
I got 12
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