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August 1, 2014

August 1, 2014

Posted by **Kelly Barnes** on Tuesday, September 30, 2008 at 9:47am.

- Physics -
**Sara**, Sunday, October 2, 2011 at 10:17pmYea, I have the same problem except the numbers are a little different does anyone know an equation that could help?

- Physics -
**Amal**, Wednesday, November 6, 2013 at 12:48pmHorizontal components of the forces are as follows:

T(sin Θ) = ma --- Equation 1

and the vertical components of the forces are

T(cos Θ) = mg --- Equation 2

where

T = tension in the string

Θ = angle that string makes with the vertical

m = mass of the object

a = acceleration = 28/6 = 4.667 m/sec^2

g = acceleration due to gravity = 9.8 m/sec^2 (constant)

Dividing Equation 1 with Equation 2,

T(sin Θ)/T(cos Θ) = ma/mg

and simplifying the above,

tan Θ = 4.667/9.8

tan Θ = 0.476

Θ = arc tan 0.476

Θ = 25.5 degrees

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