Since you know that they all had the same number of singles and doubles, you have only three unknowns to solve for. Let x be the number of singles (and doubles) for Mo, y be that number for Larry, and z be that number for Curly
x = 3y
y = 4z
2x + 2y + 2z < 200
6y + 2y + y/2 < 200
8.5 y < 200
x, y, and z must be integers. See what combinations will work.
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