Posted by alexis on Monday, September 29, 2008 at 1:17am.
First find the enclosed region between the curves. It looks like it goes from (x = 0, y = 0) to (x = 2, y = 4)
Then perform the integration from x = 0 to 2 of 2 pi(2x - x^2)(2-x)dx. This is a series of thin ring-shaped areas centered on the x=2 vertical line
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