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March 29, 2015

March 29, 2015

Posted by **ll** on Sunday, September 28, 2008 at 9:14pm.

- math studies -
**ll**, Sunday, September 28, 2008 at 10:13pmanyone????

- math studies -
**Reiny**, Sunday, September 28, 2008 at 11:56pmfor the AS

S_{n}= n/2(-8 + n-1)

= n/2(n-9)

for a GS

S_{n}= 8(1-.5^n)/(1-.5)

so n/2(n-9) > 8(1-.5^n)/(1-.5)

n/2(n-9) > 16(1-.5^n)

n^2 - 9n > 32 - 32(.5^n)

32(.5)^n + n^2 - 9n - 32 > 0

set it equal to zero and attempt to solve it.

This would be a very nasty equation to solve, except you know that n has to be a whole number, so do some trial and error calculations.

eg. n = 2 we get -38 > 0 which is false

if n = 5 we get -44 > 0 which is false

if n = 20 we get 188 > 0 which is true

So somewhere between n=5 and n=20 there should be a solution

(n=12 ---> 4.0078 > 0 mmmmhhh?)

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