Posted by Julie on Sunday, September 28, 2008 at 4:28pm.
the iteration formula x_(n+1)=x_(n)  (cos(x_(n)))(sin(x_(n))) + R(cos(x_(n))^2)x_n, where R is a positive constant, was obtained by applying Newton's Method to some function f(x). What was f(x)? What can this formula be used for?

newton's method  Damon, Sunday, September 28, 2008 at 6:56pm
g(x) = f(x)R
look for zero of g(x)
Xn+1 = Xn g(Xn)/g'(Xn)
here we have
Xn+1 = Xn (f(Xn)R)/f'(Xn)
Xn+1 =Xn f(Xn)/f'(Xn) + R/f'(Xn)
so here
f(x)/f'(x) = cos x sin x
R/f'(x) =  R x cos^2 x
so
f' = 1/(x cos^2x)
f = cos x sin x * 1/(x cos^2 x) = sin x/x cos x
I am not sure I have all your parentheses right and it does not quite check out but that is the idea.