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September 30, 2014

September 30, 2014

Posted by **Vana** on Saturday, September 27, 2008 at 1:26pm.

lim x --> negative infinity

9 square root over x^2-1

divided by

x + 4

- calculus -
**drwls**, Saturday, September 27, 2008 at 7:48pmI assume you want

Lim 9 sqrt(x^2-1)/(x+4)

x-> -inf

When x becomes very large and negative, the numerator approaches 9|x| (assuming you take only the positive square root) and the denominator approaches x. The fraction therefore approaches -9.

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