We've been working on extraction of known/unknown compound mixtures lately, and we have to give equations for the acid-base reactions that occurs between HCl, NaOh and (a) R-COOH (b) R-NH2, and (c) Neutral compounds (naphthalene and triphenylmethanol)
For (a) carboxylic acids, I wrote:
R-COOH + NaOH --> R-COONa + H20
R-COONa + HCl --> R-COOH + NaCl
(I'm not sure if I am supposed to give the equation of carboxylic acid's subsequent rxn with HCl after NaOH, but I don't know how to do it otherwise)
what about for NH2?
what about neutral compounds?
please explain also. Thanks so much!!!!
For (a) carboxylic acids, I wrote:
R-COOH + NaOH --> R-COONa + H20 This is OK. I don't know if its required or not but you can also show the ionization of RCOONa ==> RCOO^- + Na^+.
R-COONa + HCl --> R-COOH + NaCl
(I'm not sure if I am supposed to give the equation of carboxylic acid's subsequent rxn with HCl after NaOH, but I don't know how to do it otherwise)
This is right the way you have it but I would interpret the question as meaning the reaction of RCOOH + HCl for which I would write no reaction.
For the RNH2, this is a base.
RNH2 + HCl ==> RNH3Cl ==> RNH3^+2 + Cl^-
RNH2 + NaOH ==> I would write N. R.; however, some weak bases react with strong bases (such as NaOH) to give NH3 gas but this happens only under very strong conditions; i.e., the NaOH is concentrated and sometimes the mixture is heated. I think, for extraction purposes, the N.R. for NaOH is the proper choice.
For neutral compounds being extracted under the influence of acid or base conditions, I don't believe neutral compounds are affected by HCl or NaOH.
I hope I have interpreted the questins properly.
Thank you so much!! =)
C6H5COOH+HCl
write an equation to explain the interaction of the compound,RNH3Cl with NaOH
equation to show interaction of the compound RNH3Cl with NaOH
To determine the acid-base reactions involving (b) R-NH2 and (c) neutral compounds, let's first understand the behavior of these substances.
(b) R-NH2 (amines):
Amines, such as R-NH2, are organic compounds that act as weak bases. They contain an amino group (NH2) attached to a hydrocarbon (R group). When amines react with acids, they undergo protonation, where the amine accepts a proton (H+), resulting in the formation of an ammonium salt.
The equation for the acid-base reaction between R-NH2 and HCl is:
R-NH2 + HCl --> R-NH3+Cl-
For example, if R = methyl, the reaction would be:
CH3NH2 + HCl --> CH3NH3+Cl-
(c) Neutral compounds (naphthalene and triphenylmethanol):
Neutral compounds, as the name suggests, do not exhibit acidic or basic behavior because they do not contain readily ionizable hydrogen or functional groups responsible for acid-base reactions. Therefore, they do not undergo acid-base reactions with HCl or NaOH.
Hence, for neutral compounds like naphthalene and triphenylmethanol, no acid-base reactions occur with HCl or NaOH.
In summary:
(a) Carboxylic acids (R-COOH):
R-COOH + NaOH --> R-COONa + H2O (Neutralization reaction)
R-COONa + HCl --> R-COOH + NaCl (Acid-base reaction)
(b) Amines (R-NH2):
R-NH2 + HCl --> R-NH3+Cl- (Acid-base reaction)
(c) Neutral compounds (naphthalene and triphenylmethanol):
No acid-base reactions with HCl or NaOH occur for neutral compounds.