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posted by Kim on Saturday, September 27, 2008 at 1:51am.
given the functions: f(x) = x^2 - 1, g(x) = x/x + 2 Why is x^2 - 1/x^2 + 1 the equation of (g o f)(x)?
assume you forgot parentheses g(x) = x /(x+2) g = (x^2-1)/(x^2-1+2) = (x^2-1)/(x^2+1)
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