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A gaseous mixture of and contains 30.8 nitrogen by mass. What is the partial pressure of oxygen in the mixture if the total pressure is 505mmHG ?

I am getting .41 * (505/750)= .27

.27 is my answer, is this right.

  • Chemistry -

    30.8 percent N2 by mass
    69.2 precent O2 by mass

    Now you need to convert those to moles

    Assume 1000 g total
    308/28=moles of N2
    692/32 moles of O2

    Now do those moles as a percent of total moles.

    Then, multiply 505mmHg by the percent of O2 moles.

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