Posted by mb on Friday, September 26, 2008 at 9:44am.
The horizontal velocity component remains
Vx = 18.0 m/s
during the fall to the beach.
The vertical component of velocity (measured positive upwards) is
Vy = - gt
The time t that it takes to reach the beach when falling from height H is given by solving
H = (g/2) t^2
Therefore t = sqrt (2H/g) = 3.19 s
That answers your second question. Use that value of t to compute Vy at impact and from that and Vx get the angle of impact.
The speed of impact is sqrt[Vx^2 + Vy^2]
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