Posted by shan on .
A horse runs off of a 11 meter high cliff into the sea. The horse is running at a speed of 3.6 m/s. How much time does the horse spend in the air? How far from the base of the cliff is the horse when it hits the water?

physics 
drwls,
Time in the air is given by:
(1/2) g T^2 = 11 m
V * T = horizontal distance traveled 
physics 
bobpursley,
First, how long in the air?
h=1/2 g t^2 solve for t.
How far away horizontally?
d=rt
d=3.6m/s * time