Posted by **shan** on Thursday, September 25, 2008 at 7:30pm.

A horse runs off of a 11 meter high cliff into the sea. The horse is running at a speed of 3.6 m/s. How much time does the horse spend in the air? How far from the base of the cliff is the horse when it hits the water?

- physics -
**drwls**, Thursday, September 25, 2008 at 8:06pm
Time in the air is given by:

(1/2) g T^2 = 11 m

V * T = horizontal distance traveled

- physics -
**bobpursley**, Thursday, September 25, 2008 at 8:07pm
First, how long in the air?

h=1/2 g t^2 solve for t.

How far away horizontally?

d=rt

d=3.6m/s * time

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