Posted by shan on Thursday, September 25, 2008 at 7:30pm.
A horse runs off of a 11 meter high cliff into the sea. The horse is running at a speed of 3.6 m/s. How much time does the horse spend in the air? How far from the base of the cliff is the horse when it hits the water?

physics  drwls, Thursday, September 25, 2008 at 8:06pm
Time in the air is given by:
(1/2) g T^2 = 11 m
V * T = horizontal distance traveled

physics  bobpursley, Thursday, September 25, 2008 at 8:07pm
First, how long in the air?
h=1/2 g t^2 solve for t.
How far away horizontally?
d=rt
d=3.6m/s * time
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