physics
posted by shan on .
A horse runs off of a 11 meter high cliff into the sea. The horse is running at a speed of 3.6 m/s. How much time does the horse spend in the air? How far from the base of the cliff is the horse when it hits the water?

Time in the air is given by:
(1/2) g T^2 = 11 m
V * T = horizontal distance traveled 
First, how long in the air?
h=1/2 g t^2 solve for t.
How far away horizontally?
d=rt
d=3.6m/s * time