Posted by **jennifer** on Thursday, September 25, 2008 at 10:22am.

A wire is stretched from the ground to the top of an antenna tower. The wire is 20 feet long. The height of the tower is 4 feet greater than the distance from the tower's base to the end of the wire. Find the height of the tower.

20 ft.= w

x.4 = height of tower

something like this?

- math -
**drwls**, Thursday, September 25, 2008 at 11:52am
I must assume that the wire's base is attached at some distance from the bottom of the tower, like a "guy-wire".

(Broken Link Removed)

Let the tower's height be H and the length of the wire be L = 20.

Use the Pythagorean theorem:

20^2 = H^2 + (H-4)^2

and solve for H.

400 = 2 H^2 -8H + 16

H^2 -4H -192

(H-16)(H+12) = 0

Take the positive root, H = 16 feet.

The tower's base is sqrt (20^2 - 16^2) = 12 feet from where the cable touches the ground.

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