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October 30, 2014

Homework Help: chemistry

Posted by Kazhmir on Wednesday, September 24, 2008 at 11:49pm.

The following is a question on a lab I do not understand and need help with (thank you).

Topic: Hardy-Weinberg

In this Scenario, we will assign initial genotypic frequencies.
1. Record your class population's data in Table 3A.
2. Record your assigned genotype in Table 3B.
Find a partner and begin mating, as you did for scenario one.
NOTE: The double recessive genotype is lethal, so offspring who inherit the aa genotype will die. If you produce an offspring with the aa genotype, your offspring will die.Since our populatino is to have zero-population growth, parents who produce aa offspring must continue to mate until two viable offspring are produced. For the purposes of the excersis, "aa" individuals in the parental generation will not be considered lethal; instead we will assume the lethality emerges onlt in the F1 generation. Individuals in the parental generation with the aa phenotype sshould ensure they do not mate with another aa individual.
4. Again, you mate five times, recording the genotypes of your offspring in Table 3B and circling which offspring's genotype you assumed.

THE FOLLOWING IS MY DATA:
Table 3A: CLASS DATA TABLE FOR SCENARIO: SELECTION AGAINST RECESSIVE GENE (PARENTAL GENERATION)
Total number of individuals
nAA=12
nAa=15
naa=0
Total:27

Genotypic frequencies
p^2=
nAA/nTotal=0.444

2pq=
nAa/nTotal= 0.555

q^2=
naa/nTotal = 0

Allele frequencies
p = freq(A) = 0.722
q = freq() = 0.278

Table 3B: INDIVIDUAL DATA TABLE FOR SCENARIO 2

My initital Genotype = AA

Generation
F1
F2
F3
F4
F5

Offspring 1
Aa
AA
AA
Aa
Aa

Offspring 2:
Aa
AA
AA
AA
AA

My final (F5) genotype: AA


THE FOLLOWING IS THE ACTUAL QUESTION I AM HAVING A PROBLEM WITH:

Perform the chi-square test for Scenario 2, and answer the questions that follow.

Table 3D: CHI SQUARE DATA FOR SCENARIO 2:

Null Hypothesis:___________________

Expected results for AA: ____________
Expected results for Aa: ____________
Expected results for aa: ____________

Observed results for AA: ____________
Observed results for Aa: ____________
Observed results for aa: ____________


Calculation of chi square statistic:
x^2 = (O − E)2/E

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