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October 24, 2014

October 24, 2014

Posted by **arya** on Wednesday, September 24, 2008 at 9:23pm.

- math -
**bobpursley**, Wednesday, September 24, 2008 at 9:39pmThink of x^n = (x^(n+1)) / x

so if x^1 =x, then x^0 = (x^1) / x = x / x =1

If x = 0 then: 0^1 = 0, so x ^ 0 = 0 / 0

now x / n heads towards (positive or negative) infinity as n becomes closer to 0.

As infinity is not a number, x / 0 has no numeric solution.

- math -
**arya**, Wednesday, September 24, 2008 at 9:42pmthanks-

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