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September 1, 2015

Homework Help: Chemistry

Posted by Tri on Tuesday, September 23, 2008 at 6:56pm.

2HCr4- + 3HS03- + 5H+ -> 2Cr3+ + 3SO4^2- + 5H20.


At t=0, 0.0249 mols of HCr04- are loaded in to 250ml of solution. After 1/10 of an hour, 0.00852 mol of HCrO4- remain. Assuming the solution volume remained the same, how many grams of water were formed per second during this interval of time on average?

TIA!

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