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February 1, 2015

February 1, 2015

Posted by **amanda** on Tuesday, September 23, 2008 at 4:48pm.

- statistics -
**MathGuru**, Tuesday, September 23, 2008 at 9:13pmLet's gather the data:

Height (x): mean = 69, sd = 3

Weight (y): mean = 190, sd = 42

Correlation: r = 0.41

Regression equation is in this format:

predicted y = a + bx

...where a = intercept and b = slope.

To find the equation, you need to substitute the information given in the problem into a workable formula:

predicted y = (rSy/Sx)X - (rSy/Sx)xbar + ybar

...where r = correlation, Sy = sd of y, Sx = sd of x, and X is the variable in 'a + bx' equation.

Note: xbar = mean of x; ybar = mean of y.

Therefore: predicted y = [(0.41)(42)/(3)]X - [(0.41)(42)/(3)]69 + 190 = 5.74X - 206.06

predicted y = -206.06 + 5.74x

Check the math, then substitute the weights given for x, solving for predicted y.

I hope this will help.

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