For each of the following chemical reactions:

a.)classify the reaction as combination, decomposition,single replacement, or double replacement.
b.)complete the word equation.
c.)using the formulas for both reactants and products, balance the chemical equation.

1. tin(IV)nitrate + magnesium ---> ?
2. potassium oxide + water ---> ?
3. cobalt(III) + lead(II)acetate---> ?
4. aluminum bicarbonate ---^--> ?
5. copper(II)hydroxide + phosphoric acid ---> ?

Single replacement. You get magnesium nitrate and tin.

Combination - you get potassium hydroxide.
single replacement - you get cobalt acetate and lead
decomp - you get aluminum, carbon dioxide, and hydrogen gas
double replacement - you get copper phosphate and water

I will be happy to critique your thinking. Repost with your thinking.

I am just having problems balacing out the reactions.

These look ok to me except for the decomposition of aluminum bicarbonate. First, I can't find aluminum bicarbonate OR aluminum carbonate listed in The Merck Index. Assuming it exists, I would think CO2, H2O, and the metal oxide as the products upon heating.

For balancing, here is the first one.
Sn(NO3)4 + 2Mg ==> 2Mg(NO3)2 + Sn
If you will explain the problem you are having with balancing, perhaps we can help you understand how to do them.

I have:

1.)Sn(NO3)4 + 2Mg----> 2Mg(NO3)2 + Sn

2.)K2O + H20 ----> 2KOH

3.)CO2(SO4)3 + Pb(C2H3O2)2 ----> CO(CH3COO)2 4H20 + Pb

4.)Al(HCO3)3---> AlCO2 + H2

5.)Cu(OH)2 + H3PO4----> Cu3(PO4)2 + H2O

5. copper(II)hydroxide + phosphoric acid ---> double replacement - you get copper phosphate and water

Shouldnt this one be single replacement?

Did I balance them correctly?

I'm just saying i know its like 5 and a half years late but for 4 its:

Al(HCO3)3 ---> Al2(CO3)3 + CO2 + H2O

2Al(HCO3)3 ---> Al2(CO3)3 + H2O + CO2 but this isnt balaced right anyway so

To classify the reactions and complete the word equations, and then balance the chemical equations for each of the given reactions, we need to follow a systematic approach. Let's go through each reaction one by one:

1. tin(IV)nitrate + magnesium
a.) Classification: This is a single replacement reaction because magnesium is replacing tin(IV) in the compound.
b.) Word equation: Tin(IV)nitrate + magnesium -> magnesium nitrate + tin
c.) Balanced chemical equation: Sn(NO3)4 + Mg -> Mg(NO3)2 + Sn

2. potassium oxide + water
a.) Classification: This is a combination reaction because potassium oxide and water are reacting together to form a single compound.
b.) Word equation: Potassium oxide + water -> potassium hydroxide
c.) Balanced chemical equation: K2O + H2O -> 2KOH

3. cobalt(III) + lead(II)acetate
a.) Classification: This is a double replacement reaction because the positive ions of the reactants are swapping places.
b.) Word equation: Cobalt(III) + lead(II)acetate -> cobalt(II)acetate + lead(III)
c.) Balanced chemical equation: Co + Pb(C2H3O2)2 -> Co(C2H3O2)2 + Pb

4. aluminum bicarbonate
a.) Classification: This appears to be a decomposition reaction because a compound is breaking down into simpler substances.
b.) Word equation: Aluminum bicarbonate -> aluminum + carbon dioxide + water
c.) Balanced chemical equation: Al(HCO3)3 -> Al + 3CO2 + 3H2O

5. copper(II)hydroxide + phosphoric acid
a.) Classification: This is a double replacement reaction because the positive ions of the reactants are swapping places.
b.) Word equation: Copper(II)hydroxide + phosphoric acid -> copper phosphate + water
c.) Balanced chemical equation: Cu(OH)2 + H3PO4 -> Cu3(PO4)2 + H2O

By following these guidelines, we can properly classify and balance the given chemical reactions.