The width of a rectangle is 2 ft less than the length. The area is 8 ft squared. Find the length and the width.
therefore the width would be 4ft and the length would be 2ft because 4ft times 2ft is 8 ft.
a=LxW
a=2x4
a=8ft
when you say "8 feet squared" that would mean you have a square 8 feet by 8 feet, which would give you 64 square feet.
You probably meant to say 8 square feet ??
If so, then the width is x, and the length is x+2
then
x(x+2) = 8
x^2 + 2x - 8 = 0
(x+4)(x-2) = 0
so x - -4 (no way) or
x = 2
width is 2, lenth is 4, check : 2x4 = 8
To find the length and width of the rectangle, we can set up an equation using the given information.
Let's say the length of the rectangle is "L" ft.
According to the given information, the width of the rectangle is 2 ft less than the length. So, the width can be represented as "L - 2" ft.
The formula for the area of a rectangle is length multiplied by width:
Area = Length * Width
Given that the area is 8 ft², we can write the equation as:
8 = L * (L - 2)
Now, let's solve this equation to find the length (L) and width (L - 2).
Expanding the equation, we have:
8 = L² - 2L
Rearranging the equation to form a quadratic equation, we get:
L² - 2L - 8 = 0
To solve this quadratic equation, we can factor it:
(L - 4)(L + 2) = 0
Setting each factor equal to zero, we get two possible solutions for L:
L - 4 = 0 or L + 2 = 0
Solving for L, we have two possibilities:
L = 4 or L = -2
Since length cannot be negative, we discard L = -2.
Therefore, the length of the rectangle is 4 ft.
Now, to find the width, substitute the value of the length (L = 4) into the expression L - 2:
Width = 4 - 2 = 2 ft
Hence, the length of the rectangle is 4 ft, and the width is 2 ft.