How many values of x make each statement true? Explain your reasoning.

a) 3x+3=3(x+1)
b) x-4-x=0

I don't get what the question is telling me to do.
Help?

for the first one:

3x+3=3(x+1) expand it to get
3x+3 = 3x+3
0=0
this is a true statement, so any value of x makes the original statement true.
This is an example of an "identity"

for the second:
x-4-x=0 , so
-4 = 0
this is a False statement, so NO value of x will make the original statemtent true

Thank you sooo much.

:]

i need help in intergers

-+-=-

and

+++=+

-++=-

++-=+

To answer this question, we need to solve the given equations and find out how many values of x satisfy each equation. Let's analyze each statement separately:

a) 3x + 3 = 3(x + 1)

To solve this equation, we need to distribute the 3 on the right side of the equation:

3x + 3 = 3x + 3

Notice that both sides of the equation are the same, which means that the equation is true for all values of x. In other words, any value of x will satisfy this equation. Thus, there are infinite values of x that make this statement true.

b) x - 4 - x = 0

In this equation, we have two terms involving x. Simplifying it, we get:

-4 = 0

Notice that the left side of the equation is a constant value (-4), and the right side is 0. They are not equal, which means there is no value of x that satisfies this equation. In other words, there are no values of x that make this statement true.

In summary:
a) There are infinite values of x that satisfy the equation 3x + 3 = 3(x + 1).
b) There are no values of x that satisfy the equation x - 4 - x = 0.