two tuning forks are struck at the same time. One tuning fork has a frequency 20hz while the second tuning fork has afrequency of 226hz.how many beats will result?

You get the 20 Hz, the 226 hz, the sum of the two and the difference of the two. The 20 and 226 are the original frequencies; the sum is one beat frequency and the difference is another beat frequency.

To determine the number of beats that will result when two tuning forks with different frequencies are struck simultaneously, we need to calculate the difference between their frequencies.

In this case, the first tuning fork has a frequency of 20 Hz, and the second tuning fork has a frequency of 226 Hz. The beat frequency is the absolute difference between these two frequencies.

Formula for beat frequency: |f1 - f2|

So, the beat frequency = |20 Hz - 226 Hz| = |-206 Hz| = 206 Hz.

Therefore, the number of beats that will result is 206 beats.