factor completely
(x+9)^2 -5(x+9)-6
how do i do this one?
Pretend it is
u^2-5u-6
factor, then substitue back in.
how about letting x+9 equal y, then your expression is
y^2 - 5y - 6
now it is easy to see the factors, once done replace y with x+9
let me know what you got
x+9=y
y^2-5y-6
(y-3)(y+2)
(x+9-3)(x+9+2)
is this it or close?
To factor the expression completely, you can use a method called grouping. Here's how you can do it step by step:
Step 1: Rewrite the expression in the form of a quadratic equation by grouping the terms with the common factor.
(x+9)^2 -5(x+9)-6
= [(x+9)^2 -5(x+9)] - 6
Step 2: Factor out the common terms from the first two terms in the parentheses.
= [(x+9)(x+9) - 5(x+9)] - 6
Step 3: Notice that both terms inside the brackets have a common factor of (x+9). Factor it out.
= (x+9)(x+9 - 5) - 6
Step 4: Simplify the expression inside the brackets.
= (x+9)(x+4) - 6
So, the factored form of the expression is (x+9)(x+4) - 6.