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July 29, 2014

July 29, 2014

Posted by **jennifer** on Sunday, September 21, 2008 at 10:20am.

(2s + 5)(s+1)=-1

am I on the right track?

2s^2 +2s=5s=5+-1

2s^2+7s+5=-1

2s^2+7s=-6

where do i go from here?

- MATH -
**drwls**, Sunday, September 21, 2008 at 10:30amYou need to get zero one one side of the equation, and then try to factor the quadratic term on the other side.

2s^2 + 7s +6 = 0

(2s+3)(s+2) = 0

Both 2s + 3 and s+2 are sero, so

s = -3/2 or -2

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