solve
(2s + 5)(s+1)=-1
am I on the right track?
2s^2 +2s=5s=5+-1
2s^2+7s+5=-1
2s^2+7s=-6
where do i go from here?
You need to get zero one one side of the equation, and then try to factor the quadratic term on the other side.
2s^2 + 7s +6 = 0
(2s+3)(s+2) = 0
Both 2s + 3 and s+2 are sero, so
s = -3/2 or -2