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January 29, 2015

January 29, 2015

Posted by **jennifer** on Sunday, September 21, 2008 at 10:11am.

6x^2 - 5x +1 = 0

is this correct?

6x^2 - 2x - 3x + 1=0

-2x(-3x+1) 1(-3x +1)

(2x-1)=0 (3x-1)=0

x=1/2 x=1/3

- MATH -
**drwls**, Sunday, September 21, 2008 at 10:43amThe final answer is correct but there is an intermediate step that is wrong. You should have written

(2x-1)(3x-1) = 0

as the factoring step.

You did break up the quadratic correctly into

-2x(3x-1) + (-3x+ 1)

which can be written

(-3x+1)(-2x+1) = (3x-1)(2x-1)

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