MATH
posted by jennifer .
solve
6x^2  5x +1 = 0
is this correct?
6x^2  2x  3x + 1=0
2x(3x+1) 1(3x +1)
(2x1)=0 (3x1)=0
x=1/2 x=1/3

The final answer is correct but there is an intermediate step that is wrong. You should have written
(2x1)(3x1) = 0
as the factoring step.
You did break up the quadratic correctly into
2x(3x1) + (3x+ 1)
which can be written
(3x+1)(2x+1) = (3x1)(2x1)