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March 29, 2017

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What mass of limestone (in kg) would be required to completely neutralize a 15.2 billion-liter lake that is 1.9×10−5 M in sulfuric acid and 8.6×10−6 M in nitric acid?

  • chemistry - ,

    For the sulfuric acid..

    moles limestone=moles acid

    for the nitric acid,
    moles limestone=2*moles nitric acid

    I will be happy to check your calculations

  • chemistry - ,

    5.2*10^5

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