Posted by **Akitsuke** on Sunday, September 21, 2008 at 4:30am.

Find the area of the surface generated by revolving the given curve about the y-axis.

8xy^2=2y^6+1 , 1<=y<=2.

thank you so much.. :)

- Integral Calculus -
**drwls**, Sunday, September 21, 2008 at 8:01am
You need x as a function of y to do the integration.

In this case, x(y) = 1/(8y^2) + (y^4)/4

To get the surface area, evaluate:

Integral of 2 pi x(y) dy

(y = 1 to 2)

The indefinite integral is

2 pi [-1/(24y^3) + y^5/20]

= pi[(y^5)/10 - 1/(24y^3)]

Evaluate it at y=2 and y=1, and take the difference. Check my math.

## Answer This Question

## Related Questions

- Calculus II/III - A. Find the integral of the following function. Integral of (x...
- Calc - Set up and evaluate the definite integral for the area of the surface ...
- asdf - Find a definite integral indicating the area of the surface generated by ...
- Calc - Set up and evaluate the definite integral for the area of the surface ...
- calculus - Find the volume of the solid generated by revolving the region about ...
- Math - Find the area of the surface generated by revolving the curve y = (x + 3...
- MATH - Find the volumes of the solids generated by revolving the region in the ...
- Calculus II - Find the volume of the solid generated by revolving R about the x-...
- Calculus - The graph of the curve y2=10 x+10 is a parabola, symmetric with ...
- Calculus - Find the volume of the solid generated by revolving the following ...

More Related Questions