Posted by mark on Saturday, September 20, 2008 at 8:47pm.
When t = -pi/2, x = cos(-pi) = -1 and y = sin -pi/2 = -1
When t = -pi/4, x = cos(-pi/2) = 0 and y = sin -pi/4 = -0.707
When t = 0, x = 1 and y = 0
When t = pi/4, x = 0 and y = .707
When t = pi/2, x = -1 and y = 1
When t = 3pi/4, x = cos 3pi/2 = 0 and y = sin3pi/4 = 0.707
When t = pi, x = 1 and y = 0
The particle follows a smooth curve. The curve looks like a parabola that is open to the left.
You can use a trigonometric identity to show that the curve is
x = 1 - 2y^2, which is indeed a parabola.
wow thx a lot man
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