Two forces, F1 and F2 , act at a point. F1 has a magnitude of 8.80N and is directed at an angle of 64.0 degree above the negative x axis in the second quadrant. F2 has a magnitude of 7.00N and is directed at an angle of 52.8 degree below the negative x axis in the third quadrant.
1. What is the x component of the resultant force?
2. What is the y component of the resultant force?
3. What is the magnitude of the resultant force?
This is the answer provide by Drwls:
1. -8.80 cos 64.0 -7.00 cos 52.8
2. 8.80 sin 64.0 - 7.00 sin 52.8
3. Take the square root of the sum of squares of the two components given above.
Can someone show me how to express the answer for 1 and 2 in Newtons unit. Thanks
Those answers are already in Newtons.
Use your calculator to find the sines and cosines and multiply.
For example:
-8.80 cos 64 = -8.80*.43837
= -3.51 N
12
To express the answers for 1 and 2 in Newtons unit, you simply need to perform the calculations and include the unit "N" in your final answers. Here's how you can express the answers for 1 and 2:
1. Start with the given values for the x-components of the forces:
-8.80 cos 64.0 - 7.00 cos 52.8
Evaluate this expression using a calculator:
-8.80 * cos(64.0) - 7.00 * cos(52.8) ≈ -11.261 N
So, the x component of the resultant force is approximately -11.261 N.
2. Start with the given values for the y-components of the forces:
8.80 sin 64.0 - 7.00 sin 52.8
Evaluate this expression using a calculator:
8.80 * sin(64.0) - 7.00 * sin(52.8) ≈ 3.174 N
So, the y component of the resultant force is approximately 3.174 N.
Therefore, the answer for 1 is approximately -11.261 N and the answer for 2 is approximately 3.174 N.