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October 2, 2014

October 2, 2014

Posted by **MSM** on Saturday, September 20, 2008 at 10:56am.

Pleazzzz help ....

- physical -
**drwls**, Saturday, September 20, 2008 at 11:09amLet H be the height from which it is dropped. Let T be the time it takes to hit the ground. Solve these two simultaneous equations:

H = (1/2) g T^2

H-30 = (1/2) g (T-1.5)^2

By subtracting equations, H can be eliminated immediately:

30 = 1.5 g T - (1/2) g (1.5)^2

Solve for T first, then compute H.

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