Determine the number of moles of
N atoms in a sample of C7H5(NO2)3 that has the same number of O atoms as 12.6g C6H12O6
i'm working on the same project as you. i'll post my answer once i get to this question.
This question is answered the same way as the one you posted yesterday asking for the mols N in 42.5 g Mg(NO3)2.
Well, let's break this down with a little chemistry humor.
Firstly, we need to determine the number of moles of O atoms in 12.6g C6H12O6. But don't worry, they won't O-bstruct us too much!
Using the molar mass of C6H12O6, which is approximately 180.16 g/mol, we can calculate the number of moles of C6H12O6 in 12.6g. And be-hold, we find it to be around 0.07 moles.
Now, since we're looking for the number of moles of N atoms in a sample of C7H5(NO2)3 that has the same number of O atoms, we need to find the mole ratio between N and O.
In C7H5(NO2)3, each NO2 has 2 O atoms, so there are a total of 6 O atoms in C7H5(NO2)3.
Thus, the mole ratio between N atoms and O atoms in C7H5(NO2)3 is 1:6.
Since we know the number of moles of O atoms in C6H12O6 is 0.07, we can multiply that by the mole ratio to find the number of moles of N atoms.
0.07 moles * (1 mole N atoms / 6 moles O atoms) = approximately 0.01 moles of N atoms.
So, we have about 0.01 moles of N atoms in the sample of C7H5(NO2)3.
That's enough chemistry for now, hope it didn't nitrogen-tle your brain too much!
To determine the number of moles of N atoms in the given sample of C7H5(NO2)3, we first need to find the molar mass of C7H5(NO2)3.
C7H5(NO2)3 contains seven carbon atoms (C), five hydrogen atoms (H), three nitrogen atoms (N), and six oxygen atoms (O).
Now let's calculate the molar mass of C7H5(NO2)3, taking into account the atomic masses of each element:
- Carbon (C) has an atomic mass of 12.01 g/mol.
- Hydrogen (H) has an atomic mass of 1.01 g/mol.
- Nitrogen (N) has an atomic mass of 14.01 g/mol.
- Oxygen (O) has an atomic mass of 16.00 g/mol.
To calculate the molar mass, multiply the number of atoms for each element by their atomic mass and sum them up:
Molar mass of C7H5(NO2)3 = (7 × 12.01) + (5 × 1.01) + (3 × 14.01) + (6 × 16.00)
Now, let's calculate the molar mass:
Molar mass of C7H5(NO2)3 = 84.07 + 5.05 + 42.03 + 96.00
= 227.15 g/mol
Next, we need to calculate the number of moles of C6H12O6 in 12.6 g. The molar mass of C6H12O6 is obtained using the same steps as above.
Molar mass of C6H12O6 = (6 × 12.01) + (12 × 1.01) + (6 × 16.00)
= 72.06 + 12.12 + 96.00
= 180.18 g/mol
To calculate the number of moles, we can use the formula:
moles = mass / molar mass
Number of moles of C6H12O6 = 12.6 g / 180.18 g/mol
Simplifying:
Number of moles of C6H12O6 ≈ 0.07 mol
Since the number of moles of oxygen (O) atoms in C6H12O6 is equal to the number of moles of nitrogen (N) atoms in C7H5(NO2)3, we can deduce that:
Number of moles of N atoms in C7H5(NO2)3 ≈ 0.07 mol
Therefore, the number of moles of N atoms in the given sample of C7H5(NO2)3 is approximately 0.07 moles.