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March 6, 2015

March 6, 2015

Posted by **Kim-lee** on Wednesday, September 17, 2008 at 10:57pm.

A ball is shot from the ground into the air. At a height of 9.1 m, its velocity is observed to be v = 7.6i + 6.1j m/s

To what maximum height does the ball reach?

the answer is suppose to be 11m

- wow...Phys...this has me COMPLETELY clueless -
**drwls**, Wednesday, September 17, 2008 at 11:40pmThe vector velocity component that goes with the "j" unit vector is the vertical component. At 9.1 m height, the ball will rise until the vertical component becomes zero. That additional height H can be obtained from energy considerations:

g H = (1/2)(6.1 m/s)^2

which tells you that

H = 1.9 m

Add that to 9.1 m for the answer.

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