Posted by Brandon on .
As a traffic light turns green, a waiting car starts with a constant acceleration of 6.0 m/second squared. At the instant the car begins to accelerate, a truck with the constant velocity of 21 m/ second squared passes in the next lane. HINT:Set the 2 distance equations equal to each other. How far will the car travel before it overtakes the truck? How fast will the car be traveling when it overtakes the truck?

Physics 
bobpursley,
The "Hint" is the solution.
distancecar1=1/2 a*t^2
distancecar2=vo*t + 1/2 a t^2
but car2 has a=0
set distances equal, so
1/2 at^2=vot and solve for t. 
Physics to bobursley 
Barndon,
can u go back to my problem and explain it differently because my teacher has only taught us 4 equations of motion and they r d=(v intial +v final)/2 times t, v final=v intial+at, d= v intial(t)+1/2at^2, v final^2=v intial^s + 2ad

Physics to bobursley 
Brandon,
please can u answer me i am stressing out

Physics 
bobpursley,
No, I cant. consider your third equation, isn't it what I used?

Physics for bobpursley 
Brandon,
ohhhhhhhhhhh i get it now thanks