Posted by Brandon on Wednesday, September 17, 2008 at 3:58pm.
The "Hint" is the solution.
distancecar1=1/2 a*t^2
distancecar2=vo*t + 1/2 a t^2
but car2 has a=0
set distances equal, so
1/2 at^2=vot and solve for t.
can u go back to my problem and explain it differently because my teacher has only taught us 4 equations of motion and they r d=(v intial +v final)/2 times t, v final=v intial+at, d= v intial(t)+1/2at^2, v final^2=v intial^s + 2ad
please can u answer me i am stressing out
No, I cant. consider your third equation, isn't it what I used?
ohhhhhhhhhhh i get it now thanks
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