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November 22, 2014

November 22, 2014

Posted by **Ace** on Tuesday, September 16, 2008 at 11:53pm.

1.4 cm in length, and the electrons enter with a speed of 1× 105 m/s and leave with a speed of 1.5 × 108 m/s.

a. What is their acceleration over this 1.4 cm length? Answer in units of m/s2.

b. How long is the electron in the accelerating region? Answer in units of s.

- college physics -
**Anonymous**, Wednesday, September 17, 2008 at 12:49amBE CAREFUL OF UNITS

The neck length is in cm!

For a constant acceleration:

s = distance

v1 = initial velocity

v2 = final velocity

a = acceleration

t = time

s = (v1)(t) + (1/2)(a)(t^2)

s and v1 are given

v2 = v1 + (a)(t)

so (a)(t) = v2 - v1

v1 and v2 are given

substitute for (a)(t) in the first equation to solve for time.

acceleration = dv/dt = (v2 - v1)/t

- college physics -
**Kristie**, Wednesday, September 17, 2008 at 6:33pmi did not understand that! I NEED HELP!

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