Monday

March 2, 2015

March 2, 2015

Posted by **nj** on Tuesday, September 16, 2008 at 10:17pm.

- physics -
**Anonymous**, Tuesday, September 16, 2008 at 11:44pmFor constant acceleration with 0 initial velocity, the distance is:

distance = (1/2) (acceleration)(time^2)

If D= the total distance to the ground:

D = (1/2)g(TotalTime^2)

(1/2)D=(1/2)g(MidpointTime^2)

or

(1/2)g(TotalTime^2)= 2[(1/2)g(MidpointTime^2)]

(TotalTime^2) = 2(MidpointTime^2)

the problem states MidpointTime=1.6s

Substitute and solve for the total time

d=1/2at^2

a is the acceleration of gravity, t is given as 1.6s. Plug those in and solve for d. The problem states that is halfway.

**Answer this Question**

**Related Questions**

physics - A wrecking ball is hanging at rest from a crane when suddenly the ...

physics - A wrecking ball is hanging at rest from a crane when suddenly the ...

physics - A wrecking ball is hanging at rest from a crane when suddenly the ...

Physics, please help - Hello, I don't know how about to answering this question...

PHYSICS - A 1250 KG wrecking ball is lifted to a height of 12.7 m above its ...

Algebra 1 Answer Evaluation - The height of a soccer ball kicked from the ground...

physics - A 6840 N wrecking ball hangs from the end of a steel cable. What is ...

algebra 1 NEED NOW!!! PLEASE HELPPP - The height of a soccer ball that is kicked...

algebra 1 NEED NOW!!! PLEASE HELPPP - The height of a soccer ball that is kicked...

Math - A ball is dropped from a height of 36 feet. The quadratic equation d=1/2 ...