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March 29, 2015

March 29, 2015

Posted by **nj** on Tuesday, September 16, 2008 at 10:17pm.

- physics -
**Anonymous**, Tuesday, September 16, 2008 at 11:44pmFor constant acceleration with 0 initial velocity, the distance is:

distance = (1/2) (acceleration)(time^2)

If D= the total distance to the ground:

D = (1/2)g(TotalTime^2)

(1/2)D=(1/2)g(MidpointTime^2)

or

(1/2)g(TotalTime^2)= 2[(1/2)g(MidpointTime^2)]

(TotalTime^2) = 2(MidpointTime^2)

the problem states MidpointTime=1.6s

Substitute and solve for the total time

d=1/2at^2

a is the acceleration of gravity, t is given as 1.6s. Plug those in and solve for d. The problem states that is halfway.

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