x^2−2xy+y^2−9

What are we doing? Factoring?

if so....

x^2−2xy+y^2−9
= (x-y)^2 - 3^2, do you see the difference of squares?

= (x-y+3)(x-y-3)

yes factoring and thanx!

The expression you provided, x^2−2xy+y^2−9, appears to be a quadratic polynomial in two variables, x and y. Quadratic polynomials often represent equations of parabolas in the x-y plane.

To further analyze this expression, we can rearrange it as (x^2 - 2xy + y^2) - 9. The expression within the parentheses, x^2 - 2xy + y^2, can be factored as (x - y)^2 using the difference of squares formula.

Therefore, our expression can be rewritten as (x - y)^2 - 9. Now, we have a difference of squares, which can be factored further as (x - y - 3)(x - y + 3).

So, the expression x^2−2xy+y^2−9 can be factored as (x - y - 3)(x - y + 3).