math
posted by mitch .
How would you solve for x in this equation:
(x^29)(2x1)=0

For the problem, a value of x which makes a factor 0 is a solution.
(x^29)(2x1) = 0
factoring (x^29) further
(x+3)(x3)(2x1) = 0
For each factor, what value of x will make the term 0?
The first term, (x+3), will be 0 for x=3.
The second term is 0 for x=?
The third term is 0 for x=?