Posted by **mitch** on Monday, September 15, 2008 at 7:30pm.

How would you solve for x in this equation:

(x^2-9)(2x-1)=0

- math -
**Quidditch**, Monday, September 15, 2008 at 8:04pm
For the problem, a value of x which makes a factor 0 is a solution.

(x^2-9)(2x-1) = 0

factoring (x^2-9) further

(x+3)(x-3)(2x-1) = 0

For each factor, what value of x will make the term 0?

The first term, (x+3), will be 0 for x=-3.

The second term is 0 for x=?

The third term is 0 for x=?

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